4(n+2)(n+5)=280in^3

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Solution for 4(n+2)(n+5)=280in^3 equation:


Simplifying
4(n + 2)(n + 5) = 280in3

Reorder the terms:
4(2 + n)(n + 5) = 280in3

Reorder the terms:
4(2 + n)(5 + n) = 280in3

Multiply (2 + n) * (5 + n)
4(2(5 + n) + n(5 + n)) = 280in3
4((5 * 2 + n * 2) + n(5 + n)) = 280in3
4((10 + 2n) + n(5 + n)) = 280in3
4(10 + 2n + (5 * n + n * n)) = 280in3
4(10 + 2n + (5n + n2)) = 280in3

Combine like terms: 2n + 5n = 7n
4(10 + 7n + n2) = 280in3
(10 * 4 + 7n * 4 + n2 * 4) = 280in3
(40 + 28n + 4n2) = 280in3

Solving
40 + 28n + 4n2 = 280in3

Solving for variable 'n'.

Reorder the terms:
40 + -280in3 + 28n + 4n2 = 280in3 + -280in3

Combine like terms: 280in3 + -280in3 = 0
40 + -280in3 + 28n + 4n2 = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(10 + -70in3 + 7n + n2) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(10 + -70in3 + 7n + n2)' equal to zero and attempt to solve: Simplifying 10 + -70in3 + 7n + n2 = 0 Solving 10 + -70in3 + 7n + n2 = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.

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